Test

https://zhuanlan.zhihu.com/p/24709748 矩阵求导术 x=(dAs)TN1(dAs) δM1=M1(δM)M1 dx(scalar)=(Ads)TN1(dAs)+(dAs)TN1(Ads)=2(dAs)TN1(Ads) dx=(xs)Tds xs=2ATN1(dAs)=0 s=(ATN1A)1ATN1d No.MethodSpecificationPaperMap-making methodsTegmark19971GeneralizedCOBEW=[AtMA]1AtM2BinaveragingW=[AtA]1At3COBEW=[AtN1A]1AtN14Wiener1W=SAt[ASAt+N]15Wiener2W=[S1+AtN1A]1AtN16SaskatoonW=[ηS1+AtN1A]1AtN17TE96W=ΛSAt[ASAt+N]1,(WA)ii=18TE97W=Λ[ηS1+AtN1A]1AtN1,(WA)ii=19Maximum probabilityNonlinear method if non-Gaussian10Maximum entropyNonlinear method